Distance from Brownsville, TX to San Angelo, TX

From: Brownsville, County: State: Texas
To: San Angelo, County: State: Texas
Distance: 505 miles
Travel time: 8 h 31 min
Passengers:

How far is from Brownsville, TX to San Angelo, TX?

How many miles is Brownsville, TX to San Angelo, TX?

The distance between Brownsville, TX and San Angelo, TX is 505 mi by car. The travel time is 8 hours and 31 minutes.





505 mi 8 h 31 min
1.
Head southeast on Shidler Drive
0 ft
2.
Turn right onto Rockwell Drive
0.2 mi
3.
Keep right onto Rockwell Drive
0.2 mi
4.
Turn right onto Los Ebanos Boulevard
0.2 mi
5.
Go straight onto North Expressway
0.3 mi
6.
Take the ramp
0.2 mi
7.
Merge left onto North Expressway (I 69E)
22.8 mi
8.
Keep right towards I 2 West: McAllen
29.8 mi
9.
Take the ramp towards I 69C North: Edinburg
0.8 mi
10.
Continue onto I 69C
16.4 mi
11.
Keep left onto I 69C
41.1 mi
12.
Make a slight left onto US 281
13.9 mi
13.
Continue onto Fallfurias Expressway
0.3 mi
14.
Continue onto Fallifurias Expressway (US 281)
78 mi
15.
Keep left onto Nueces Street (US 281)
14.7 mi
16.
Continue onto US 281
0 ft
17.
Take the ramp onto US 281
31.2 mi
18.
Keep left onto I 37
37.4 mi
19.
Take the ramp towards Cesar East Chavez
0.2 mi
20.
Turn left onto East César E. Chávez Boulevard
1.4 mi
21.
Take the ramp on the right towards I 10 West
0.2 mi
22.
Merge left onto South Pan Am Expressway (I 10)
0 ft
23.
Keep right towards I 10 West: El Paso
0.8 mi
24.
Keep left onto McDermott Freeway (I 10)
46.5 mi
25.
Take the ramp towards US 87 North: Fredericksburg
0.2 mi
26.
Turn right onto US Highway 87 (US 87)
20.2 mi
27.
Continue onto South Washington Street (US 87)
1.2 mi
28.
Turn left onto East Main Street (US 87)
1.5 mi
29.
Keep right onto North US Highway 87 (US 87)
35.5 mi
30.
Go straight onto US 87
5.4 mi
31.
Turn left onto Fort McKavitt Street (US 87)
1.4 mi
32.
Continue onto United States Highway 87; United States Highway 377 (US 87)
27.3 mi
33.
Continue left onto Commerce Street (US 87)
0.3 mi
34.
Go straight onto United States Highway 87 (US 87)
38.7 mi
35.
Go straight onto US 87
36.4 mi
36.
Turn left onto West Avenue N
0.5 mi
37.
You have arrived at your destination, on the left
0 ft



How much does it cost to drive from Brownsville, TX to San Angelo, TX?

The fuel cost by car depend on several factors such as the distance traveled, the driving conditions (traffic jam, slow driving, normal driving, race driving), fuel consumption of the vehicle, and the current price of fuel.

The fuel cost with petrol from Brownsville, TX to San Angelo, TX is 61.46$. In the above calculation, the petrol price is considered to be 3.82$ per gallon and the petrol consumption of the car is 31.4 miles per gallon.
For 2 passengers in carpooling, the cost of this trip is 30.73$ (61.46/2) per passenger.
For 3 passengers in the car, the cost of this trip is 20.49$ (61.46/3) per passenger.
For 4 passengers in the car, the cost of this trip are 15.37$ (61.46/4) per passenger.


Fuel cost = (505.27 mi / 31.4 mpg) x 3.82$ per gallon = 61.46$

In more detail, the result is obtained:

Fuel needed = Distance / Car fuel consumption = miles / car Consumption = 505.27 mi / 31.4 mpg = 16.1 gallons

Fuel needed = 16.1 gallons

Fuel cost = Fuel needed x Price per gallon = 16.1 gallons x 4$ per gallon = 61.46 $

Fuel cost from Brownsville, TX to San Angelo, TX = 61.46 $


Consumption is measured in miles per gallon. 31.4 mpg means that a car could travel 31.4 miles with a gallon petrol fuel. The price of fuel is in dollar per gallon. 1 gallon is 3.78541178 liters.


How much do you pay to travel from Brownsville, TX to San Angelo, TX by diesel car (diesel cost estimator)?

The trip with diesel fuel from Brownsville, TX to San Angelo, TX costs 37.87 $. In the above calculation, the diesel price is considered to be 3.92$ per gallon and the diesel consumption of the car is 52.3 mpg. For only one passenger the cost of the trip is 37.87 $.
For 2 passengers in carpooling, the cost of this trip is 18.94 $ (37.87/2) per passenger.
For 3 passengers in the car, the cost of this trip is 12.62 $ (37.87/3) per passenger.
For 4 passengers in the car, the cost of this trip is 9.47 $ (37.87/4) per passenger.