Distance from Irving, TX to Keller, TX

From: Irving, County: State: Texas
To: Keller, County: State: Texas
Distance: 24.1 miles
Travel time: 32 min
Passengers:

How far is from Irving, TX to Keller, TX?

How many miles is Irving, TX to Keller, TX?

The distance between Irving, TX and Keller, TX is 24.1 mi by car. The travel time is 32 minutes.





24.1 mi 32 min
1.
Head west
0 ft
2.
Turn right
0 ft
3.
Turn left onto Virginia Street
0.1 mi
4.
Turn left onto West Pioneer Drive
0.9 mi
5.
Turn right onto TX 356
1.5 mi
6.
Take the ramp towards TX 183: Fort Worth
0.5 mi
7.
Merge left onto Airport Freeway (TX 183)
12.1 mi
8.
Take the ramp towards I 820 West
0.7 mi
9.
Merge left onto Northeast Loop
1.3 mi
10.
Take exit 20B towards Rufe Snow Drive
0.3 mi
11.
Go straight onto Northeast Loop 820
0.2 mi
12.
Turn right onto Rufe Snow Drive
0.8 mi
13.
Make a slight right to stay on Rufe Snow Drive
0.1 mi
14.
Turn right to stay on Rufe Snow Drive
2.1 mi
15.
Continue onto Rufe Snow Road
0.3 mi
16.
Continue onto Rufe Snow Drive
2.7 mi
17.
Turn left onto Bear Creek Parkway
0.3 mi
18.
You have arrived at your destination, on the right
0 ft


How much does it cost to drive from Irving, TX to Keller, TX?

The fuel cost with petrol from Irving, TX to Keller, TX is 2.94$(3.82$/gal, 31.4mpg).
For 2 passengers: 1.47$ (2.94/2).
For 3 passengers: 0.98$ (2.94/3).
For 4 passengers: 0.74$ (2.94/4).


Fuel cost = (24.05 mi / 31.4 mpg) x 3.82$ per gallon = 2.94$

In more detail, the result is obtained:

Fuel needed = Distance / Car fuel consumption = miles / car Consumption = 24.05 mi / 31.4 mpg = 0.8 gallons

Fuel needed = 0.8 gallons

Fuel cost = Fuel needed x Price per gallon = 0.8 gallons x 4$ per gallon = 2.94 $

Fuel cost from Irving, TX to Keller, TX = 2.94 $


How much do you pay to travel from Irving, TX to Keller, TX by diesel car (diesel cost estimator)?

The trip with diesel fuel from Irving, TX to Keller, TX costs 1.8 $ (3.92$/gal, 52.3 mpg).
For 2 passengers: 0.9 $ (1.8/2).
For 3 passengers: 0.6 $ (1.8/3).
For 4 passengers: 0.45 $ (1.8/4).