Distance from San Angelo, TX to Seymour, TX

From: San Angelo, County: State: Texas
To: Seymour, County: State: Texas
Distance: 194 miles
Travel time: 3 h 26 min
Passengers:

How far is from San Angelo, TX to Seymour, TX?

How many miles is San Angelo, TX to Seymour, TX?

The distance between San Angelo, TX and Seymour, TX is 194 mi by car. The travel time is 3 hours and 26 minutes.





194 mi 3 h 26 min
1.
Head east on West Avenue N
0.5 mi
2.
Turn left onto South Bryant Boulevard (US 87)
0.2 mi
3.
Continue onto South Koenigheim Street (US 87)
1.4 mi
4.
Continue onto North Bryant Boulevard (US 87)
0.1 mi
5.
Turn right onto West 6th Street (US 277)
0 ft
6.
Take the ramp on the left onto US 277
0.3 mi
7.
Merge left onto East Houston Harte Expressway (US 67)
3.5 mi
8.
Continue onto US Highway 67 (US 67)
30.2 mi
9.
Continue onto Hutchings Avenue (US 67)
2.9 mi
10.
Keep left onto US 83
79 mi
11.
Make a slight right onto East Court Plaza (US 83)
0 ft
12.
Continue onto Commercial Avenue (US 83)
75 mi
13.
Take the ramp onto US 183-B Business
0.4 mi
14.
Turn left onto Main Street (US 183-B Business)
0.8 mi
15.
Turn left onto East Oregon Street
0 ft
16.
Turn right
0 ft
17.
You have arrived at your destination, on the right
0 ft



How much does it cost to drive from San Angelo, TX to Seymour, TX?

The fuel cost by car depend on several factors such as the distance traveled, the driving conditions (traffic jam, slow driving, normal driving, race driving), fuel consumption of the vehicle, and the current price of fuel.

The fuel cost with petrol from San Angelo, TX to Seymour, TX is 23.65$. In the above calculation, the petrol price is considered to be 3.82$ per gallon and the petrol consumption of the car is 31.4 miles per gallon.
For 2 passengers in carpooling, the cost of this trip is 11.83$ (23.65/2) per passenger.
For 3 passengers in the car, the cost of this trip is 7.88$ (23.65/3) per passenger.
For 4 passengers in the car, the cost of this trip are 5.91$ (23.65/4) per passenger.


Fuel cost = (194.21 mi / 31.4 mpg) x 3.82$ per gallon = 23.65$

In more detail, the result is obtained:

Fuel needed = Distance / Car fuel consumption = miles / car Consumption = 194.21 mi / 31.4 mpg = 6.2 gallons

Fuel needed = 6.2 gallons

Fuel cost = Fuel needed x Price per gallon = 6.2 gallons x 4$ per gallon = 23.65 $

Fuel cost from San Angelo, TX to Seymour, TX = 23.65 $


Consumption is measured in miles per gallon. 31.4 mpg means that a car could travel 31.4 miles with a gallon petrol fuel. The price of fuel is in dollar per gallon. 1 gallon is 3.78541178 liters.


How much do you pay to travel from San Angelo, TX to Seymour, TX by diesel car (diesel cost estimator)?

The trip with diesel fuel from San Angelo, TX to Seymour, TX costs 14.54 $. In the above calculation, the diesel price is considered to be 3.92$ per gallon and the diesel consumption of the car is 52.3 mpg. For only one passenger the cost of the trip is 14.54 $.
For 2 passengers in carpooling, the cost of this trip is 7.27 $ (14.54/2) per passenger.
For 3 passengers in the car, the cost of this trip is 4.85 $ (14.54/3) per passenger.
For 4 passengers in the car, the cost of this trip is 3.64 $ (14.54/4) per passenger.