Distance from Sanford, FL to Lake Mary, FL

From: Sanford, County: Seminole State: Florida
To: Lake Mary, County: Seminole State: Florida
Distance: 5.4 miles
Travel time: 9 min
Passengers:

How far is from Sanford, FL to Lake Mary, FL?

How many miles is Sanford, FL to Lake Mary, FL?

The distance between Sanford, FL and Lake Mary, FL is 5.4 mi by car. The travel time is 9 minutes.





5.4 mi 9 min
1.
Head south on Holly Avenue
0 ft
2.
Turn left onto 24th Place
0.1 mi
3.
Turn right onto French Avenue (US 17)
2.4 mi
4.
Turn right onto Lake Mary Boulevard
2.6 mi
5.
Turn right onto 7th Street
0 ft
6.
Turn right onto Seminole Avenue
0 ft
7.
You have arrived at your destination, on the left
0 ft


How much does it cost to drive from Sanford, FL to Lake Mary, FL?

The fuel cost with petrol from Sanford, FL to Lake Mary, FL is 0.65$(3.82$/gal, 31.4mpg).
For 2 passengers: 0.33$ (0.65/2).
For 3 passengers: 0.22$ (0.65/3).
For 4 passengers: 0.16$ (0.65/4).


Fuel cost = (5.37 mi / 31.4 mpg) x 3.82$ per gallon = 0.65$

In more detail, the result is obtained:

Fuel needed = Distance / Car fuel consumption = miles / car Consumption = 5.37 mi / 31.4 mpg = 0.2 gallons

Fuel needed = 0.2 gallons

Fuel cost = Fuel needed x Price per gallon = 0.2 gallons x 4$ per gallon = 0.65 $

Fuel cost from Sanford, FL to Lake Mary, FL = 0.65 $


How much do you pay to travel from Sanford, FL to Lake Mary, FL by diesel car (diesel cost estimator)?

The trip with diesel fuel from Sanford, FL to Lake Mary, FL costs 0.39 $ (3.92$/gal, 52.3 mpg).
For 2 passengers: 0.2 $ (0.39/2).
For 3 passengers: 0.13 $ (0.39/3).
For 4 passengers: 0.1 $ (0.39/4).