Distance from Sandy, UT to Mendon, UT

From: Sandy, County: Salt Lake State: Utah
To: Mendon, County: Cache State: Utah
Distance: 94 miles
Travel time: 1 h 40 min
Passengers:

How far is from Sandy, UT to Mendon, UT?

How many miles is Sandy, UT to Mendon, UT?

The distance between Sandy, UT and Mendon, UT is 94 mi by car. The travel time is 1 hour and 40 minutes.





94 mi 1 h 40 min
1.
Head north
0 ft
2.
Turn right onto East Galena Drive
0 ft
3.
Turn left onto Flint Drive
0.5 mi
4.
Turn left onto 9400 South (UT 209)
0.8 mi
5.
Continue onto 9000 South (UT 209)
1.8 mi
6.
Take the ramp on the right towards I 15
0.1 mi
7.
Keep left towards I 15
0.2 mi
8.
Merge left towards Salt Lake City
11.5 mi
9.
Keep left onto I 15
16.4 mi
10.
Keep left onto I 15
37.9 mi
11.
Take the ramp towards US 91
0.2 mi
12.
Keep right onto I 15 Business
0.3 mi
13.
Merge left onto West 1100 South (US 91)
16.2 mi
14.
Continue onto US 89
0.4 mi
15.
Turn left onto South Center Street (UT 23)
2.2 mi
16.
Turn left onto South 100 West (UT 23)
4.9 mi
17.
Turn right onto West Center Street
0.2 mi
18.
You have arrived at your destination, on the left
0 ft



How much does it cost to drive from Sandy, UT to Mendon, UT?

The fuel cost by car depend on several factors such as the distance traveled, the driving conditions (traffic jam, slow driving, normal driving, race driving), fuel consumption of the vehicle, and the current price of fuel.

The fuel cost with petrol from Sandy, UT to Mendon, UT is 11.38$. In the above calculation, the petrol price is considered to be 3.82$ per gallon and the petrol consumption of the car is 31.4 miles per gallon.
For 2 passengers in carpooling, the cost of this trip is 5.69$ (11.38/2) per passenger.
For 3 passengers in the car, the cost of this trip is 3.79$ (11.38/3) per passenger.
For 4 passengers in the car, the cost of this trip are 2.85$ (11.38/4) per passenger.


Fuel cost = (93.69 mi / 31.4 mpg) x 3.82$ per gallon = 11.38$

In more detail, the result is obtained:

Fuel needed = Distance / Car fuel consumption = miles / car Consumption = 93.69 mi / 31.4 mpg = 3 gallons

Fuel needed = 3 gallons

Fuel cost = Fuel needed x Price per gallon = 3 gallons x 4$ per gallon = 11.38 $

Fuel cost from Sandy, UT to Mendon, UT = 11.38 $


Consumption is measured in miles per gallon. 31.4 mpg means that a car could travel 31.4 miles with a gallon petrol fuel. The price of fuel is in dollar per gallon. 1 gallon is 3.78541178 liters.


How much do you pay to travel from Sandy, UT to Mendon, UT by diesel car (diesel cost estimator)?

The trip with diesel fuel from Sandy, UT to Mendon, UT costs 7.02 $. In the above calculation, the diesel price is considered to be 3.92$ per gallon and the diesel consumption of the car is 52.3 mpg. For only one passenger the cost of the trip is 7.02 $.
For 2 passengers in carpooling, the cost of this trip is 3.51 $ (7.02/2) per passenger.
For 3 passengers in the car, the cost of this trip is 2.34 $ (7.02/3) per passenger.
For 4 passengers in the car, the cost of this trip is 1.76 $ (7.02/4) per passenger.